Question

On bombarding ₇N¹⁴ with α - particles the nuclei of the product formed after the release of a proton will be:
1. ₈O¹⁷
2. ₉F¹⁸
3. ₈O¹⁸
4. ₉F¹⁷

Answer 1

Correct Answer - Option 1 : ₈O¹⁷

Concept:

• Alpha Particles: ( ₂α ⁴ ) Alpha particles are particles with the number of protons (atomic number) 2 and the number of neutron and proton (mass number)  4. It is similar to Helium Atom.
• It is obtained from the radioactive decay process of a heavy nucleus. 

Explanation:

₇N¹⁴ bomb barded with α particles, and one proton is released and one another product is formed.  

A proton (1 P 1) is having mass number 1 and atomic number 1. 

Let another product is  _a X ^b (Atomic number a, mass number b )

So, the process can be represented as 

7N14  + 2α 4 → a X b  + ₁ P ¹ --  (1)

By law of conservation of mass, the atomic number and mass number should be equal to both sides of the equation.

Comparing mass number in both side of equation (1)

14 + 4 = b + 1

⇒ b = 14 + 4 - 1 = 17

Comparing atomic number

7 + 2 = a + 1

⇒ a = 7 +2 -1 = 8

So, mass number is 17 and atomic number is 8.

From the given options 8O17 is having a mass number 17 and the atomic number is 8.

So, the correct option is 8 O 17