Given: A.P. = 11, 8, 5, 2…
Here a1 = a = 11;
d = a2 – a1 = 8 – 11 = -3
If possible, take – 150 as the nth term of the given A.P.
an = a + (n – 1) d
⇒ -150 = 11 + (n – 1) × (-3)
⇒ -150 = 11 – 3n + 3
⇒ 14 – 3n = – 150
⇒ 3n= 14 + 150 = 164
∴ n = \(\frac{164}{3}\) = 54\(\frac{2}{3}\)
Here n is not an integer.
∴ -150 is not a term of the given A.P.