4, 7, 10, 13, 16, …….
Adding ‘5’ to each term of the above A.P. we get
4 + 5, 7 + 5, 10 + 5, 13 + 5, 16 + 5,…
9, 12, 15, 18, 21, ……
In the list obtained the first term
a1 = 9; a2 = 12, a3 = 15, a4 = 18,
Also a2 – a1 = 12 – 9 = 3
a3 – a2 = 15 – 12 = 3
a4 – a3 = 18 – 15 = 3 ……………………………………
i.e.,
d = a2 – a1 = a3 – a2 = a4 – a3 = …. = 3
∴ The resulting list forms an A.P.