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Divide 3y^3 + 2y^2 + y by ‘y’ and write division fact.

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Divide 3y3 + 2y2 + y by ‘y’ and write division fact.

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(3y3 + 2y2 + y) ÷ y = \(\frac {3y^3}{y} + \frac {2y^2}{y} + \frac yy\)

= 3y2 + 2y + 1 

Division fact = (3y2 + 2y + 1) y 

= 3y2 + 2y2 + y

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