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If AP and AQ are the two tangents a circle with centre O, so that ∠POQ = 110°. Then ∠PAQ is equal to 

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If AP and AQ are the two tangents a circle with centre O, so that ∠POQ = 110°. Then ∠PAQ is equal to 

a) 60° 

b) 70° 

c) 80° 

d) 90°

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1 Answer

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Correct option is b) 70°

In □ OPAQ, 

∠OPA = ∠OQA = 90° 

∠POQ = 110° 

∴ ∠O + ∠P + ∠A + ∠Q = 360° 

⇒ 90° + 90° + 110° + ∠PAQ – 360° 

⇒ ∠PAQ = 360° – 290° = 70°

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