Let us write 45 and 75 in the form of a = bq + r where a = 75, b = 45
∴ 75 = 45 (1) + 30
Again using lemma a = bq + r, where
a = 45, and b = 30,
we get, 45 = 30 (1) + 15
then 30 = 15 (2) + 0
Here we get remainder ‘0’ when we divide it by 15.
So 15 is HCF of 45 and 75.