Question

Express log₅ 125 = 3 in its exponential form.

Answer 1

We know that 

if log_a x = N then a^N = x 

So, log₅ 125 = 3 => 5³ = 125 

[∵ x = 125, a = 5, N = 3] 

∵ 5³ = 125 is the exponential form of log₅ 125 = 3