Question

Find the area of a quadrilateral PQRS in which ∠QPS = ∠SQR = 90°, PQ = 12 cm, PS = 9 cm, QR = 8 cm and SR =17 cm. 

[Hint: PQRS has two parts]

Answer 1

Area of ΔQPS = 1/2 x base x height

= 1/2 x 9 x 12

= 54cm²

In ΔQPS QS² = PQ² + PS²

∴ □PQRS = ΔQPS + ΔQSR 

= 54 + 60= 114 cm²