The volume of a cuboid formed with the measures 20 cm × 18 cm × 16 cm
(V1) = l1b1h1
= 20 × 18 × 16
Volume of a cube (V2) = s3
s = 4 cm (given)
∴ V2 = (s)3 = (4)3 = 4 × 4 × 4 cm3
∴ No. of cubes are required
= \(\frac{v_1}{v_2} = \frac{20\,\times\,18\,\times16}{4\,\times\,4\,\times\,4}\)
= 90