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Calculate the dissipation in power across 20Ω resistor for the FM signal v(t)= 20 cos(6600t+ 10sin2100t) 

a. 5W 

b. 20W 

c. 10W 

d. 400W

1 Answer

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Best answer

a. 5W 

A standard FM signal is represented by

v(t) = Ac cos(2πfct + kfsin2πfmt)

Ac = carrier amplitude fc = carrier frequency

kf = modulation index

fm = modulating frequency

kf = frequency deviation/modulating frequency

the power dissipated across 20Ω resistor is given by

Vrms 2/R

=(20/√2)2/R= 5W

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