i) AB = PR
∠B = ∠P
∠C = ∠Q
Now by angle sum property ∠A = ∠R
∴ By A.S.A, ΔABC ≅ ΔRPQ
ii) ΔADB ≅ ΔCBD by A.S.A.
∠ABD = ∠CDB
DB = DB
iii) AB = CD
∠A = ∠D
∠B = ∠C (by angle sum properly
By A.S.A
ΔABO ≅ ΔDCO
iv) We can say whether the triangles are congruent or not, at least one pair of sides should be given equal.