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The ratio of the sums of m and n terms of an AP is m^2 :n^2. Show that the ratio of the mth and nth terms is (2m -1): (2n - 1).

+1 vote
asked Feb 2 in Mathematics by Kundan kumar (49,122 points) 30 312 806

The ratio of the sums of m and n terms of an AP is m2 :n2. Show that the ratio of the mth and nth terms is (2m -1): (2n - 1).

1 Answer

+1 vote
answered Feb 2 by Vikash Kumar (144,654 points) 8 10 19
Best answer

Let a be the first term and d the common difference of the given AP. Then, the sums of m and n terms are given by

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