Total hydration energy of Al3+ and 3CI- ions of AlCl3 (ΔHhydration)
= (Hydration energy of Al3+ + 3 x hydration energy of Cl-)
= [-4665 + 3(-381)] kJ mol-1
= - 5808 kJ mol-1
This amount of energy is more than that required for the ionisation of Al into Al3+ (Ionisation energy of Al to Al3+). Due to this reason, AlCl3 becomes ionic in aqueous solution. In aqueous solution, it exists in ionic form as below: