Question

Solve the following systems of equations:
44/(x+y)+30/(x−y)= 4
55/(x+y)+40/(x−y)= 13

Answer 1

Then, the system of the given equations becomes

Multiplying equation (i) by 4 and equation (ii) by 3, we get

Subtracting equation (iv) by equation (iii), we get

Adding equation (v) and (vi), we get

Hence, solution of the given system of equations is x= 8, y =3.