Use app×
Ask a Question
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE

(​​sin 35°/cos 55°) - (tan 12°/cot 78°) - (sin 18°/cos72°)

← Prev Question Next Question →
0 votes
283 views
in Mathematics by (40.5k points)
closed by

\(\frac{sin35°}{cos55°}\,-\frac{tan12°}{cot78°}\,-\frac{sin18°}{cos72°}= ?\)

(A) 1 

(B) 0 

(C) 3 

(D) -1

Play Quiz Game >

1 Answer

+1 vote
by (43.6k points)
selected by
 
Best answer

(D) 151

\(\frac{sin35}{cos55}\,\,-\frac{tan12}{cot78}\,\,-\frac{sin18}{cos72} =1-1-1=-1\)

← Prev Question Next Question →

Find MCQs & Mock Test

  1. JEE Main 2025 Test Series
  2. NEET Test Series
  3. Class 12 Chapterwise MCQ Test
  4. Class 11 Chapterwise Practice Test
  5. Class 10 Chapterwise MCQ Test
  6. Class 9 Chapterwise MCQ Test
  7. Class 8 Chapterwise MCQ Test
  8. Class 7 Chapterwise MCQ Test

Related questions

0 votes
1 answer
Evaluate: tan 35°/ cot 55° + cot 78°/tan 12° - 1
asked Mar 6, 2020 in Trigonometry by ShasiRaj (56.4k points)
+2 votes
1 answer
Evaluate tan 35°/cot 55°+cot 78°/tan 12°− 1
asked Feb 15, 2018 in Mathematics by sforrest072 (130k points)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

User Contribution to Sarthaks eConnect
Managed by Sarthaks Digitizing India
...