(i) sin (cos-1(\(\frac{5}{13}\))) = \(\sqrt{1-cos^2(cos^{-1}(\frac5{13}))}\)
= \(\sqrt{1-(\frac5{13})^2}\) = \(\sqrt{\frac{13^2-5^2}{13^2}}\) = \(\frac{\sqrt{169-25}}{13}\)
= \(\frac{\sqrt{144}}{13}\) = \(\frac{12}{13}\)
(ii) cos(sin-1(-7/25)) = \(\sqrt{1-sin^2(sin^-1(-7/25))}\)
= \(\sqrt{1-(-7/25)^2}\)
= \(\frac {\sqrt{25^2-7^2}}{25}\) = \(\frac{\sqrt{625-49}}{25}\) = \(\frac{\sqrt{576}}{25}\) = \(\frac{24}{25}\)
(iii) tan(sin-1(\(\frac{15}{17}\))) = \(\cfrac{sin(sin^{-1}(\frac{15}{17}))}{cos(sin^{-1}(\frac{15}{17}))}\) = \(\cfrac{\frac{15}{17}}{\sqrt{1-sin^2(sin^{-1}(\frac{15}{17}))}}\)
= \(\cfrac{\frac{15}{17}}{\sqrt{1-\frac{15^2}{17^2}}}\) = \(\cfrac{\frac{15}{17}}{\frac{\sqrt{289-225}}{17}}\) = \(\frac{15}{\sqrt{64}}\) = \(\frac{15}8\)
(iv) cot[cosec-1(25/7)] = \(\sqrt{cosec^2(cosec^{-1}(25/7))-1}\)
= \(\sqrt{(\frac{25}7)^2-1}\) = \(\sqrt{\frac{625-49}{7^2}}=\frac{\sqrt{576}}7=\frac{24}7\)
(v) sin (tan-13/4) = \(\frac{tan(tan^{-1}3/4)}{\sqrt{1+tan^2(tan^{-1}3/4)}}\)
= \(\frac{3/4}{\sqrt{1+(3/4)^2}}\)
= \(\cfrac{\frac34}{\frac{\sqrt{16+9}}4}\) = 3/5
(vi) sec (cot-1(-5/12)) = \(\sqrt{1+\frac{1}{cot^2(cot(-5/12))}}\)
= \(\sqrt{1+\frac{1}{(-5/12)^2}}\)
= \(\sqrt{1+\frac{12^2}{5^2}}\) = \(\frac{\sqrt{25+144}}{5}\) = \(\frac{13}5\)