Answer is False.
Let the height of tower, AB = h m
The length of shadow, BC = x m
According to given question,
\(\frac{AB}{BC} = \frac {\sqrt 3}1\)
\(\frac hx = \frac{\sqrt 3}1\)
We know that,
In ΔABC,
\(\frac{AB}{BC} = \tan \theta\)
\(\tan \theta = \frac hx\)
\(\tan \theta = \frac {\sqrt 3}1\)
\(\tan \theta = {\sqrt 3}\)
\(\tan \theta = \tan 60° \)
\(\theta = 60°\)
Hence, the angle of elevation is 60°.