Let the number be n = 12 m + 8, \(m\in Z\)
(i) m = 0, then n = 8, \(\frac n {48} \) gives remainder 8.
(ii) m = 1, then n = 20, \(\frac n {48} \) gives 20 as remainder.
(iii) m = 2, then n = 32, \(\frac n {48} \) gives 32 as remainder.
(iv) m = 3, then n = 44, \(\frac n {48} \) gives 44 as remainder.
(v) m = 4, then n = 56, \(\frac n {48} \) gives 8 as remainder.
Hence, when n is divides by 48 then possible remainder are 8, 20, 32 or 44.