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x1, x2, x3, x4, x5 ∈ {1, 2,...,18} are arranged such that x1 >x2 >x3 >x4 > x5 then find probability of x2 = 7 & x4 = 11.

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x1, x2, x3, x4, x5 ∈ {1, 2,...,18} are arranged such that x1 >x2 >x3 >x4 > x5 then find probability of x2 = 7 & x4 = 11.

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Correct answer is 126/18C5

Total number of cases = 18C5

Favourable number of cases = 6 x 3 x 7 = 126

Probability = 126/18C5

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