\(f(2 ^- ) = \lim\limits_{x\to 2} \;2ax + 4 = 4a + 4\)
\(f(2^+) = \lim\limits_{x \to 2} \;bx^2 + 2 = 4b + 2\)
∵ \(f(x) \) is continuous at x = 2.
∴ \(f(2^-) = f(2^+) = f(2)\)
⇒ \(4a+ 4 = 4\) & \(4b + 2 = 4\)
⇒ \(4a = 0 \) & \(4b = 2\)
⇒ \(a = 0 \) & \(b = \frac12\)