Question

While performing a thermodynamics experiment, a student made the following observations, 

HCl + NaOH → NaCl + H₂O 

ΔH = –57.3 kJ mol^–1 

CH₃COOH + NaOH → CH₃COONa + H₂O 

ΔH = –55.3 kJ mol^–1. 

The enthalpy of ionization of CH₃COOH as calculated by the student is ______ kJ mol^–1. (nearest integer)

Answer 1

ΔH_ionisation of CH₃COOH = |-57.3 - (-55.3)|

= 2 KJ/mol