(a) Area of parallelogram = Base x Height
= (12 x 7) cm2
= 84 cm2
(b) r = Radius of semi-circle = 3.5 cm
∴ Area of semi-circle = \(\frac12 \pi r^2\)
\(= \frac 12 \times \frac{22}7 \times 3.5\times 3.5\)
\(= 19.25\, cm^2\)
(c) Area of shape/figure = Area of semi-circle + Area of triangle
\(= \frac12\pi r^2 + \frac12\times \) Base \(\times\) Height
\(= \frac 12 \times \frac{22}7 \times 3.5\times3.5+\frac 12 \times 3.5\times 3\)
\(= 19.25 + 5.25\)
\(= 24.50 \,cm^2\)
