Question

What is the ratio of number of arrangements of all letters of the word ASHOK and GEETA ?

Answer 1

Total permutations of arranging 5 letters of word ASHOK = ⁵P₅ = 5! = 120

Total permutations of arranging 5 letters of which E is repeated 2 times of word GEETA = \(\frac{5!}{2!}=\frac{120}{2}\) = 60

∴ The ratio of number of arrangements of all letters of the word ASHOK and GEETA

= \(\frac{120}{2}\) = 2: 1