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Find the unknown value:

(1) nCn-2 = 15

(2) 4.nC4 = 7.nC3

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(1) nCn-2 = 15

∴ \(\frac{n!}{(n−2)!(n−n+2)!}\) = 15

∴ \(\frac{n(n−1)(n−2)!}{(n−2)!2!}\) = 15

∴ \(\frac{n(n−1)}{2}\) = 15

∴ n(n – 1) = 30

∴ n(n – 1) = 6 × 5

∴ n(n – 1) = 6(6 – 1)

∴ n = 6

(2) 4.nC4 = 7.nC3

\(∴ 4. \frac{ni}{4i(n-4)i} = 7.\frac{ni}{3i(n-3)i}\)

\(∴ \frac{4}{24(n-4)i}= \frac{7}{6(n-3)i}\)

\(∴ \frac{1}{6(n-4)i}= \frac{7}{6(n-3)(n-4)i}\)

\(∴ \frac{1}{6}= \frac{7}{6(n-3)}\)

∴ n - 3 = 7

∴ n = 10

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