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Calculate median value of the following data set using graphic technique 

Size: 0-10,10-20,20-30,30-40,40-50,50-60 

Frequency: 3,10,20,7,6,4

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1 Answer

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Class size Frequency Cumulative frequency
0 - 10 3 3
10 - 20 10 13
20 - 30 20 33
30 - 40 7 40
40 - 50 6 46
50 - 60  4 50
n = 50

\(n = 50\)

\(\frac n2 = 50\)

Cumulative frequency which is just greater than n/2 or 25 is 33 which is of class 20 - 30.

\(\therefore \) Median class = 20 - 30

l = lower limit of median class  = 20

f = frequency of median class = 20

c.f. = cumulative frequency just before median class = 13

h = class interval = 30 - 20 = 10

\(\therefore \) Median = \(l + \frac{\frac n2 - cf}{f} \times h\)

\(= 20 + \frac{25 - 13}{20} \times 10\)

\(= 20 + \frac{12}2\)

\(= 20 + 6\)

\(= 26\)

Hence, median of the data set = 26.

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