Question

The mass of AgCl precipitated when 4.68 g of NaCl is added to a solution containing 6.8 g of AgNO₃ is

a. 4.52 g

b. 5.74 g

c. 7.18 g

d. 8.2 g

Answer 1

Correct option is b. 5.74 g

Answer 2

Correct option is (b) 5.74g

 \(AgNO_3+NaCl\longrightarrow AgCl+NaNO_3\)

Number of moles of \(NaCl=\frac{4.68}{58.5}=0.08\)

Number of moles of \(AgCl=\frac{6.8}{170}=0.04\)

\(\therefore\) \(AgNO_3\) is a limiting reagent

therefore, AgCl is formed = 0.04 mol

\(\therefore\) weight of AgCl formed \(=0.04\times143.5=5.74g.\)