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Effect of change of Pressure or volume of the Vessel on the Rate of Reaction.

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Consider a reaction

2A + B → Product 

The rate law for above reaction is 

Rate = [A]2 [B]

If volume of the Vessel is doubled, concentrations are halved. Then, new rate is given as

Rate = k[A/2]2 [B/2]

If volume of vessel is reduced to 1/4th, concentrations become 4 times. 

Then, new rate is given as: 

Rate = k[4A]2 [4B]

If at constant temperature, pressure is doubled, volume is reduced to half. Hence, concentrations are doubled. 

Then, new rate is given as:

Rate = k[2A]2 [2B]

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