Question

If the polar of P with respect to the circle x² +y² = a² touches the circle (x–f)² +(y–g)² = b² then its locus is given by the equation.

(a) (fx+gy–a²) ² = a² (x² +y²)

(b) (fx+gy–a²) ² = b² (x² +y²)

(c) (fx–gy–a²) ² = a² (x² +y²)

(d) None of these.

Answer 1

Correct option is  (b) (fx+gy–a²) ² = b² (x² +y²)