Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
51 views
in Physics by (56.9k points)
closed by

From the top of a tower of vertical height ‘h’, a ball A is projected vertically upwards with speed v0 at an angle of 60° with the horizontal. n second later a second ball B is projected horizontally with same speed v0 . The two balls colloide with one another n is

(1) \(\frac{v_0}{g}\)

(2) \(\frac{2v_0}{\sqrt{3}g}\)

(3) \(\frac{2v_0}{g}\)

(4) \(\frac{v_0}{\sqrt{3}g}\)

1 Answer

+1 vote
by (54.1k points)
selected by
 
Best answer

 (2) \(\frac{2v_0}{\sqrt{3}g}\)

In Fig. O is top of tower. Choosing co-ordinate axis as shown in Fig. and t = 0 when ball A is projected; the instantaneous co-ordinates (x1, y1) of ball A are

The instantaneous co-ordinates (x2 , y2) at t = t (t > n) of ball B are

Let P be the point where the two balls colloide with one another. Co-ordinates of ball A and B are same at this moment of time. From Eqns. (1) and (3).

From Eqns (2) and (4); we have,

obviously, from Eqns. (5) and (6) we have

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...