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Three identical blocks, of mass M each, are connected to each other by inextensible strings and are kept on a smooth horizontal floor. On applying a force F, as shown, the system moves with an acceleration a. If the tensions in the two strings are T1 and T2 , respectively, the ratios (F/T2) and (F/T1) equal respectively to

(1) 3 and 1.5

(2) 1.5 and 3

(3) 2 and 1

(4) 1 and 2

1 Answer

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Best answer

(2) 1.5 and 3

For the first mass, on the right, we have

F - T = Ma

For the second mass, we have

T2 - T1 = Ma

For the third mass, we have

T1 = Ma

Adding the three equations, we get

F = 3Ma or a = F/3M

∴ F - T2 = M.F/3M = F/3

∴ T2 = 2F/3

Also, T1 = Ma = M.F/3M = F/3

∴ F/T2 = 3/2 = 1.5

and F/T1 = 3

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