Question

A body of mass ‘m’ slides down a length l of an inclined plane with angle of inclination θ with the horizontal. Calculate its speed at the bottom of the incline. How far further will it slide on an identical horizontal surface before coming to a stop?

Answer 1

Correct answer is \(\sqrt{2gl(sin\theta -μ\,cos\theta),}\frac{l}{μ}(sin\theta-μ\,cos\theta)\)