Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
85 views
in Physics by (51.8k points)
closed by

A cylinder of mass M; radius R is set into motion on a rough horizontal surface with a linear speed v0 in forward direction and an angular speed of v0/3R in anticlockwise direction. μ is coefficient of friction between cylinder and horizontal surface. The linear speed of cylinder when it starts rolling is

(1) v0/2

(2) 4v0/5

(3) 5v0/7

(4) 7v0/9

1 Answer

+1 vote
by (52.2k points)
selected by
 
Best answer

(4) 7v0/9

Given ω0 = v0/3R.

Since v0 ≠ Rω ; the cylinder slips an horizontal surface. Consider motion about an axis fixed to ground and passing through the instantaneous point of contact of cylinder with ground. There is no net torque about this axis; therefore angular momentum is conserved. Let v and ω denote the linear and angular speed when cylinder stops slipping i.e. it starts rolling. Then

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...