The area bounded by y = ƒ(x), the x-axis and the ordinates x = 1 & x = b is (b – 1)sin(3b + 4). Then ƒ(x) is

Question

The area bounded by y = f(x), the x-axis and the ordinates x = 1 & x = b is (b – 1) sin(3b + 4). Then f(x) is

a. (x – 1) cos(3x + 4)

b. 8sin(3x + 4)

c. sin(3x + 4) + 3(x – 1) cos(3x + 4)

d. none of the above

Answer 1

Correct options are c. sin(3x + 4) + 3(x – 1) cos(3x + 4)