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0 votes
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in Calculus by (53.3k points)

The area of the region between the curves \(y = \sqrt{\frac{1 + sinx}{cosx}}\) and \(y = \sqrt{\frac{1 - sinx}{cosx}}\)bounded by the lines x = 0 & x = π/4 is

a. \(\int\limits_0^{\sqrt 2 - 1} \frac{t\,dt}{(1 + t^2)\sqrt {1-t^2}}\)

b. \(\int\limits_0^{\sqrt 2 - 1} \frac{4t}{(1 + t^2)\sqrt {1-t^2}}dt\)

c. \(\int\limits_0^{\sqrt 2 + 1} \frac{4t}{(1 + t^2)\sqrt {1-t^2}}dt\)

d. \(\int\limits_0^{\sqrt 2 + 1} \frac{t}{(1 + t^2)\sqrt {1-t^2}}dt\)

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1 Answer

+1 vote
by (53.6k points)

Correct option is b. \(\int\limits_0^{\sqrt 2 - 1} \frac{4t}{(1 + t^2)\sqrt {1-t^2}}dt\)

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