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Figuqre shows a potentiometer with a cell of 20 V and internal resistance of 0.04Ω maintaining a potential drop across the resistor wire AB. A standard cell which maintains a constant emf 1.02 V gives a balance point at 67.3 length of the wire. To ensure very low currents drawn from the standard cell, a very high resistance of 600 kΩ is put in series with it which is shorted close to the balance point. The standard cell is replaced by a cell of unknown emf E and the balance point found similarly turn out to be 82.3 cm length of the wire. The value of E from the above given data is found to be 1.25 volt. We wish to determine the emf of, say, a themocouple (or the order of a few millivolt.

(1) To aclieve this measurement we should replace the high resistance of 600Ω with an infinite resistance.

(2) Increase the potential gradient of the potentiometer wire by a factor of at least 100.

(3) Decrease the potential gradient of the potentiometer wire by at least a factor of 100 by connecting suitable low resistance in series with the potentiometer wire.

(4) Decrease in potential gradient of potentiometer wire by a factor of more than 100 by connecting a suitable high resistance in series with the potentiometer wire.

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(4) Decrease in potential gradient of potentiometer wire by a factor of more than 100 by connecting a suitable high resistance in series with the potentiometer wire.

The potential gradient of given wire is

Usually R is of the order of a few ohm while L is of the order of 400 cm to 1000 cm.

It follows that the balance length for a small e.m.f. would be only a few cm. We would need to reduce the value of s by a factor of at least hundred or so. This can be achieved by adding a suitable high resistance in series with the potentiometer wire.

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