Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
359 views
in Circles by (51.1k points)

The locus of a point such that the tangents drawn from it to the circle x2 + y– 6x – 8y = 0 are perpendicular to each other is

a. x+ y– 6x – 8y – 25 = 0

b. x2 + y2 + 6x – 8y – 5 = 0

c. x+ y2 – 6x + 8y – 5 = 0

d. x2 + y– 6x – 8y + 25 = 0

Please log in or register to answer this question.

1 Answer

+1 vote
by (51.4k points)

a. x+ y– 6x – 8y – 25 = 0

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...