Question

ABCD is a square of unit side. It is folded along the diagonal AC so that the plane ABC is perpendicular to the plane ACD. The shortest distance between the lines AB & CD is

(a) \(\sqrt{\frac 32}\)

(b) \(\frac 32\)

(c) \(\frac 23\)

(d) \(\sqrt{\frac 23}\)

Answer 1

Correct option is (d) \(\sqrt{\frac 23}\)

Let A(1, 0, 0) B(1, 1, 0), C(0, 1, 0), D(0, 0, 0)

Equation of CD is