Let ω be a complex cube root of unity (i.e.ω ≠ 1). A fair die is thrown three times. If r1, r2, & r3 are the numbers obtained on the die, then the probability that \(\omega ^{r_1} + \omega^{r_2} + \omega^{r_3} = 0\) is
(a) 1/18
(b) 1/9
(c) 2/9
(d) 1/36