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0 votes
11.2k views
in Physics by (194 points)
edited by

In the circuit of given figure, the final voltage drop across the capacitor C is

In the circuit of given figure, the final voltage drop across the capacitor is

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1 Answer

+1 vote
by (10.8k points)

Current through r1 and r2 connected in series will be I = V/(r1+r2)

 So PD across r2 = I*r2= Vr2/(r1+r2)

Hence the voltage drop across the capacitor will be = Vr2/(r1+r2)

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