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In △ABC, medians AD and BE are drawn. If AD = 4, ∠DAB = π/6 and ∠ABE = π/3, then the area of △ABC is (in square units)

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In △ABC, medians AD and BE are drawn. If AD = 4, ∠DAB = π/6 and ∠ABE = π/3, then the area of △ABC is (in square units)

(a) \(\frac{64}{3\sqrt 3}\)

(b) \(\frac{8}{3\sqrt 3}\)

(c) \(\frac{16}{3\sqrt 3}\)

(d) \(\frac{32}{3\sqrt 3}\)

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Correct option is (d) \(\frac{32}{3\sqrt 3}\) 

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