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0 votes
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in Trigonometry by (51.4k points)

Inradius of a circle which is inscribed in an isosceles triangle one of whose angle is 2π/3 is √3, then area of triangle is

(a) 4√3

(b) 12 – 7√3

(c) 12 + 7√3

(d) None of these

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1 Answer

+1 vote
by (51.1k points)

Correct option is (c) 12 + 7√3

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