Equal masses of ice at 0 degree Celsius and steam at 100 degree Celsius are mixed . The resultant temperature will be

Question

Equal masses of eyes at 0 degree Celsius and steam it is 100 degree Celsius are mixed the resultant temperature will be

Answer 1

Heat loss by water = Heat gain by water

\(mS(100 - T_0) = mL_f + mS(T_0 - 0)\)

\(m \times (100- T_0) = m[80 + 1 \times T_0]\)

\(100 - T_0 = 80 + T_0\)

\(20 = 2T_0\)

\(T_0 = 10°C\)