Question

At what pH, given half cell MnO₄^- (0.1 M) | Mn²⁺ (0.001 M) will have electrode potential of 1.282 V? __________ (Nearest Integer)

Given:

\(E^0_{MnO_4^-/Mn^{2+}}= 1.54 V, \frac{2.303RT}{F} = 0.059V\)

Answer 1

Correct answer is 3.