Let r and h be the radius and height of the solid right circular cylinder respectively.
Let S be the total surface area of the solid right circular cylinder.
Given that r = 10cm and S = 880 m2
2 x 22/7 x r x10 = 880
r = \(\frac{880\ \times\ 7}{2\times22\times10}\) m
r = 14 m
Volume of cylinder = πr2h
= 22/7 x 14 x 14 x 10 m3
= 6160 m3