Correct option is (C) 3%
Given, error in measurement of radius of sphere = 1 %
As, we know that,
\(V = \frac 43 \pi r^3\)
\(\frac{\Delta V}V = 3 \frac{\Delta r}{r}\)
\(\frac{\Delta V}V \times 100 = 3\left(\frac{\Delta r}r\times 100\right)\)
\(= 3 \times 1\)
\(= 3\) %
