Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
255 views
in Physics by (49.0k points)
closed by

In van der Waals' gas equation \(\left(p +\frac{a}{V^2}\right)(V-b) = RT\), the dimensional formula for constants a and b respectively are 

(A) [ML3T-2], [ML-1]

(B) [ML5T-2], [L3]

(C) [L3], [ML5T-2]

(D) [ML-1], [ML3T-2]

1 Answer

+1 vote
by (48.9k points)
selected by
 
Best answer

Correct option is (B) [ML5T-2], [L3]

Given, \(\left(p +\frac{a}{V^2}\right)(V-b) = RT\)

Dimension of b = Dimension of V

= [L] x [L] x [L]

= [L3]

Dimension of p = Dimension of a/V2

⇒ Dimension of a = p x V2

⇒ Dimension of F/A x V2

⇒ Dimension of a = \(\frac{[MLT^{-2}]}{[L^2]}\times [L^3]^2\)

= [ML5T-2]

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...