The correct option (b) 2
Explanation:
when I1 & I2 are in same direction, B = 10μT
∴ [(μ0I1)/(2πr)] – [(μ0I2)/(2πr)] = 10μT (1)
when I1 & I2 are in opposite direction B' = 30μT
∴ [(μ0I1)/(2πr)] + [(μ0I2)/(2πr)] = 30μT (2)
(1) + (2) gives,
[(μ0I1)/(2πr)] = [(40μ0T)/(2)] = 20μ0T (3)
(1) – (2) gives,
– [(2μ0I2)/(2πr)] = – 20μ0T
i.e. [(μ0I2)/(2πr)] = 10μT (4)
Taking ratio of (3) & (4) gives
(I1/I2) = [(20μT)/(10μT)] = 2.