Correct option is (c) 7743
Let n, n + 2, n + 4, n + 6 are the given consecutive odd numbers is p = n, Q = n + 2, R = n + 4, S = n + 6 then
average = \(\frac{n + n +2 + n + 4 + n + 6}{4} = 88\) (given)
⇒ \(4n + 12 = 88\times 4\)
⇒ \(4n = 352 - 12 = 340\)
⇒ \(n = \frac{340}4 = 85\)
⇒ \(n = 85\)
\(\therefore \) P = 85, Q = 87, R = 89, S = 91
\(\therefore \) Product of Q and R = 87 x 89 = 7743