Correct option is (d) 4√3 cm
Consider a circle of radius 4 cm and center O. Tangents are drawn from point P to the circle at A and B.
A line form the center bisects the angle between the tangents.
Hence, ∠APO = 30∘
Also, ∠OAP = 90∘ ....(Angle between tangent and the radius)
Thus, tan ∠APO = \(\frac{OA}{AP}\)
⇒ tan30∘ = \(\frac{4}{AP}\)
⇒ AP = 4√3 cm