Correct option is (d) 1/6
There are 6 faces of one dice.
∴ When 2 die are thrown the number of total elementary events = 6 × 6 = 36.
In order to get a total of 3 the events are
(1, 2), (2, 1) = 2 events.
In order to get a total of 5 the events are
(2, 3), (4, 1), (3, 2), (1, 4) = 4 events.
∴ The total number of favourable evets = 2 + 4 = 6.
∴ The probability of getting a total of 3 or 5
\(=\frac{\text{number of favourable events}}{\text{number of elementary events}}\)
\(= \frac 6{36}\)
\(= \frac 16\)
